ListView background items

[valery.stroeder]

Hello,

In my Grids, a row of two is green and the others are white thanks this code :


myGrid.getView().setViewConfig(new GridViewConfig(){
@Override
public String getRowStyle(final ModelData model, final int rowIndex, final ListStore<ModelData> ds) {
String returnTemp;

if(rowIndex%2==0) {
returnTemp = "even";
} else {
returnTemp = "odd";
}
return returnTemp;
}
});


in the style.css file


.even {
background-color:green;
}
.odd {
background-color:white;
}

Is there a way to do the samething in a ListView ?

[valery.stroeder]

Noboday has a solution?

[Arno.Nyhm]

you need to do this via template in XTemplate syntax

[valery.stroeder]

Do you have an example ??

[valery.stroeder]

up?

[sven]

listView.setTemplate(getTemplate());



private native String getTemplate() /*-{
return [
'<tpl for=".">',
'<div class="{[xindex % 2 === 0 ? "even" : "odd"]} x-view-item">{name}</div>',
'</tpl>'
].join("");
}-*/;

[valery.stroeder]

Thank you, it works fine !

If i want use a different kind of condition, for example I have a ComboBox(MyObject) (called combo) and a Map<MyObject,int> (called map).
Can I use my map to conditionally set the style name ?

Something like that?

private native String test() /*-{
return [
'<tpl for=".">',
'<div class="{[xmap.get(currentObject) === 0 ? "redStyle" : "greenStyle"]} x-view-item">{name}</div>',
'</tpl>'
].join("");
}-*/;

[valery.stroeder]

Is it possible with Xtemplate ?
Should I try with another method like onRender or setViewConfig ?
Why doesn't exist a ListViewConfig ?