Grid RecordForm Plugin

If using ExtJS 3.3.0, and LovCombo, then you will need to make the following modification to Ext.ux.grid.RecordForm.js:

On line 300, replace this:

Code:

---

            // use cm editor if we have one
            if(c && c.editor && c.editor.field) {

---

With this:

Code:

---

            // use cm editor if we have one
            if(c && c.editor ) {
               
                c.editor.field = c.editor;

---

Worked for me B)
Thanks for such a useful plugin, it's a big timesaver when I just want a simple editor of a simple record.

hy j sakalos....thanks for your plugin.now, i use with mysql for database, data can display but edit or save button not work because error: cannot decode JSON object.i guess problem in line json_decode on Ext.decode(response.responseText)..any suggest for it, i use ExtJS Ver 3.3??

Check your server response, possibly on http://jsonlint.com/, to see if the server response is valid.

hmm...thanks for your response.i'll try and report it later.be success...

my server is valid response..save or edit still error, in sqlite json_decode is work, but in mysql it's not work..can you give me specified solution for this issue??thank you jsakalos....

hmmm problem solved..in mysql not begin transaction but using start transaction for update data..thank's for this thread and thread starter

--- edited ---

Hi everybody, I'm using this component and I want to set a value obtained of a combo into a textField of the recordForm but I can' do it. I have tried this:
var obj1 = Ext.getCmp('textField1');
obj1.setValue(1);
Error: obj1 is undefined
Help please. How can I access to the Fields of the recordForm?

You need to give your textfield an id.

So your code might look like this:

Code:

---

new Ext.form.TextField({
        width: '82%',
        id: 'textField1',
        name: 'textField1',
        fieldLabel: 'Text Field',
        triggerAction: 'all',
        allowBlank: true
})

---

Without the explicit id set in code, Ext gives it a weird Ext-cmp-blah ID, so you will get the undefined error.

I do not recommend to set an id, use form.findField('field-name') instead.