1. #1
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    Default simple login form with Ext.JSON.decode

    simple login form with Ext.JSON.decode


    i am trying to create a simple login function towards a php script where i JSON encode a string


    PHP code:
    $jsonString = json_encode('success');
    echo $jsonString;

    the i use Ext.JSON.decode to parse the result like this in my logincontroller:


    var result = Ext.JSON.decode(response.responseText);
    if (result.success) {
    Ext.Msg.alert(working);
    }
    else{
    Ext.Msg.alert(result);
    }


    and i get a Ext.Msg.alert saying success ;-)
    anyone that can tell me what i am doing wrong here ? :-)



  2. #2
    Sencha - Senior Forum Manager mitchellsimoens's Avatar
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    Default


    Have you inspected what the result param is? I would have expected an error decoding a string.
    Mitchell Simoens @SenchaMitch
    Sencha Inc, Senior Forum Manager
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  3. #3
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    Default


    i changed it to
    if (result == 'success') {
    and that seems to be working :-)

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