How to get simple response from server without using data.store?

[Qwentor]

I want to check the input data for existence on the server. The data must be sent to server and then I must get the answer true/false. For example if data already exists and because not saved - true, else false.

[rsqw]

Ext.Ajax.request({
url: "/cool/url",
method: "POST",
params: {
coolParam: "coolValue"
},
success: MY_COOL_SUCCESS_CALLBACK
failure: MY_COOL_FAILURE_CALLBACK
});


To make a cross-domain request use:
Ext.data.JsonP.request

Hope this helps

[Qwentor]

I can't understand how to do it in PHP code
I've done so:
ExtJS:

Ext.Ajax.request({
                                        url: "add.php",
                                        params: {
                                            number: text
                                        },
                                        success: function(){
                                            store.insert(0, new User());
                                            var record = store.getAt(0);
                                            var dataIndex = 'Number';
                                            record.beginEdit();
                                            record.set(dataIndex, text);
                                            record.endEdit();                                                                                        
                                        },
                                        failure: function() {
                                            Ext.Msg.alert('Failure!', 'This number already exists!');
                                        }
                                    });

PHP:

<?php
header('Content-Type: text/html; charset=UTF-8'); 

if ($db = @mysql_connect("localhost", "root", "123456")) { 
   mysql_select_db("test2"); 
   mysql_query("SET NAMES utf8"); 

   $number = $_POST['number'];
   $queryString = "Select `Number` FROM `table2` WHERE `Number` = '".$number."'";
   $data = mysql_query($queryString);
   $rows = mysql_num_rows($data);
   if($rows) {
        echo '{"success":"false"}';
   }
   else {
  
    $queryString = "INSERT INTO `table2` (`Number`) VALUES ('".$number."')";
    mysql_query($queryString);
    echo '{"success":"true"}';
    }
  mysql_close($db);
}
?>

But alert not works and new row is always added to grid, but if it contains data that already exists on server then this data not saved after reload page.
Therefore program always gets success: true. Why? What do I do wrong?

[hendrisoni]

You can use Ext.decode()

Ext.Ajax.request({
    url : "add.php",
    params : {
        number : text
    },
    success : function(response) {
        response = Ext.decode(response.responseText)
        if(response.success) {
            store.insert(0, new User());
            var record = store.getAt(0);
            var dataIndex = 'Number';
            record.beginEdit();
            record.set(dataIndex, text);
            record.endEdit();
        }
    }
});

[Qwentor]

Thanks! It helps me. But I've used if(response.success == 'true'),
if(response.success) not works

[hendrisoni]

it is because that is sent from php not an object. try,

echo json_encode(array('success' => true)); 

[Qwentor]

Thanks!