get a row from a grid

[eternasparta]

I think it's very simple to answer to this question:


I have simple grid with my custom store:

 //other code
     {xtype: 'grid',
            store:'SecondStore',
	        itemId: 'mainTabPanel2',
		    columns:[{header: 'Not Form Store', id:'keyId2',}, //this is not from the store
                     {header: 'From Store',  dataIndex: 'label', id:'keyId',}//from the store
     ]}

the store only populate the second column with id: keyId. In fact it have:

 fields: [
        {name: 'label'}]

And this work well.


I want to get from a function the row n°1 of this grid.

 handler: function()
    {var grid =Ext.ComponentQuery.query('grid[itemId="mainTabPanel2"]')[0];
     //var row= get row(1) <- i don't know how to get the complete row
     }

I'm working with ExtJs 4 so i can't get it with the comand
grid.getView().getRow(1);


I can't get it from the store because i want to get also the content of the column with id:keyId2 that is not stored in the store, so I can't do something like:

 grid.getStore().getAt(1);

Anyone know how to get the complete row in ExtJs 4?
thank you!

[sword-it]

Hi eternasparta,

You can use getRecords() method of the grid view class, like -

grid.getView().getRecords()[0];

For more detail read the API docs-http://docs.sencha.com/ext-js/4-1/#!/api/Ext.view.Table-method-getRecords

[sriram139]

I think getNode() is what you are looking for.
http://docs.sencha.com/ext-js/4-1/#!...method-getNode

Try printing this HTLMElement and you can see complete row element that is rendered.

Thanks,
Sriram

[eternasparta]

thank you!