1. #11
    Sencha - Ext JS Dev Team Animal's Avatar
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    If you want to load an image, create an image tag, set its src, append it to the document - the browser will then load it. If you set its class to "x-hide-offsets" it will be rendered offscreen, and you can move it into view, when you are ready.

    There's lots of things you can do, it's up to you.

  2. #12
    Sencha Premium Member MaximGB's Avatar
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    Add some fake query param to image url, ie:
    image.src = '/some/path/to/image.gif?dc=' + Ext.id();
    Use the force - read the source.

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    This is what i did

    1. Fake query: FFox is fine. IE Not refreshing
    2. Change the url with random name: like /bla/bla/math.random(): FFox is fine, IE not refreshing
    3. Senda 302 and redirect to somewhere else: Again: IE is not doing it.

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    Sooo.. Please dont hit me

    Damn IE is reporting jpeg as image/pjpeg instead of jpeg so every picture i was uploading was folling though the schema -.-

    Close please

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    Default any solution - how to use same url with different contents?

    any solution - how to use same url with different contents?


    Could we manage to find - how to use same url with different content?